countdown recursion javascript

function countdown(n){
  if (n < 1) {
    return [];
  } else {
    const arr = countdown(n - 1);
    arr.unshift(n);
    return arr;
  }
}
console.log(countdown(5)); // [5, 4, 3, 2, 1]

const recursiveRangeSum = (num, total = 0) => {  if (num <= 0) {    return total;  }  return recursiveRangeSum(num - 1, total + num);};

function countdown(n) {
  if (n < 1) {
    return [];
  } else {
    const arr = countdown(n - 1);
    arr.unshift(n);
    return arr;
  }
}
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